Nitrogen compounds
Amines are bases because the nitrogen lone pair accepts a proton, and how available that lone pair is explains why ethylamine is stronger, and phenylamine much weaker, than ammonia, and why amides are hardly basic at all. The unit shows how amines, nitriles and amides are made and interconverted, how cold diazotisation of phenylamine leads to phenol and to coloured azo dyes, and how amino acids form zwitterions, join through peptide bonds and are separated by electrophoresis.
Learning outcomes (15)
- Recall the reactions (reagents and conditions) by which primary and secondary amines are produced: (a) halogenoalkanes with in ethanol heated under pressure; (b) halogenoalkanes with primary amines in ethanol, heated in a sealed tube or under pressure; (c) amides with ; (d) reduction of nitriles with or /Ni.
- Describe the reactions by which nitriles can be produced: reaction of a halogenoalkane with in ethanol and heat.
- Recall the reactions by which hydroxynitriles can be produced: aldehydes and ketones with HCN, as catalyst, and heat.
- Describe the hydrolysis of nitriles with dilute acid or dilute alkali followed by acidification.
- Describe the basicity of aqueous solutions of amides.
- Describe the reaction of phenylamine with at room temperature.
- Describe the reaction of phenylamine with and dilute acid below to produce the diazonium salt, and the further warming of the diazonium salt with water to give phenol.
- Explain the relative basicities of aqueous ammonia, ethylamine and phenylamine.
- Identify the properties of azo compounds: (a) the coupling of benzenediazonium chloride with phenol in to form an azo compound; (b) the azo group; (c) azo compounds are often used as dyes; (d) other azo dyes can be formed by a similar route.
- Identify the reactions (reagents and conditions) by which amides are produced: (a) ammonia and an acyl chloride at room temperature; (b) a primary amine and an acyl chloride at room temperature.
- Describe the reactions of amides: (a) hydrolysis with aqueous alkali or aqueous acid; (b) reduction of the group with to form an amine.
- Explain why amides are much weaker bases than amines.
- Describe the acid-base properties of amino acids and the formation of zwitterions.
- Describe the formation of amide (peptide) bonds between amino acids to give di- and tripeptides.
- Predict the results of electrophoresis on mixtures of amino acids and dipeptides at varying pH.
IntroNitrogen compounds and classes of amines
This unit studies organic compounds that contain nitrogen: amines, nitriles, amides, diazonium salts and azo compounds, and amino acids. Amines are the building blocks of amino acids, which in turn build proteins. Nitriles are used to make amines and acids with longer carbon chains, and diazonium salts are used to make dyes and drugs.
Amines are derivatives of ammonia, , in which one or more hydrogen atoms are replaced by alkyl or aryl groups. They are classified by the number of carbon atoms joined to the nitrogen atom.
| Type | General formula | Carbon atoms on N | Example |
|---|---|---|---|
| primary amine | 1 | ethylamine, | |
| secondary amine | 2 | dimethylamine, | |
| tertiary amine | 3 | trimethylamine, | |
| quaternary ammonium salt | 4 (no lone pair left) | tetraethylammonium iodide, |
Phenylamine (aniline), , is an aromatic amine: the group is joined directly to a benzene ring. Its chemistry differs from that of alkylamines because the nitrogen lone pair interacts with the ring.
12.1Preparation of aminesOften examined
1. From halogenoalkanes and ammonia
A halogenoalkane is heated with an excess of concentrated ammonia in ethanol in a sealed tube (under pressure) at about . The tube is sealed because ammonia is a gas and would escape on heating. Ethanol is the solvent; water is avoided because hydroxide ions would turn the halogenoalkane into an alcohol.
The reaction is a nucleophilic substitution. The lone pair on the nitrogen of ammonia attacks the carbon of the halogenoalkane and the halide ion leaves. The ammonium salt formed then gives up a proton to a second ammonia molecule, freeing the amine.
ethylammonium bromide
ethylamine is released
overall
The reaction does not stop at the primary amine. Ethylamine also has a lone pair (it is an even better nucleophile than ammonia), so it attacks more bromoethane in the same two steps and gives a secondary amine. That reacts again to give a tertiary amine, and finally a quaternary ammonium salt:
diethylamine (secondary)
triethylamine (tertiary)
tetraethylammonium iodide (quaternary salt)
At the end, a strong alkali such as is added to set the free amines loose from their salts (the quaternary salt is not affected, because its nitrogen has no H to lose). The three amines are then separated by fractional distillation. Using a large excess of ammonia makes the primary amine the main product, but some secondary and tertiary amines still form, so the yield of the primary amine is low. An excess of halogenoalkane favours the quaternary salt.
2. Secondary amines from halogenoalkanes and primary amines
To make a secondary amine on purpose, the halogenoalkane is heated with a primary amine (instead of ammonia) in ethanol, in a sealed tube or under pressure. The salt formed is then treated with a base.
3. Reduction of nitriles
Alkyl or aryl nitriles are reduced to primary amines. The reducing agent is lithium aluminium hydride () in dry ether (followed by water), or sodium in ethanol. stands for hydrogen supplied by the reducing agent.
ethanenitrile gives ethylamine
Catalytic reduction: nitriles also react with hydrogen gas over a heated nickel catalyst.
propanenitrile gives propylamine
4. Reduction of amides
With the group of an amide is reduced to , giving an amine with the same number of carbon atoms.
| Starting material | Reagent and conditions | Product | Carbon chain |
|---|---|---|---|
| halogenoalkane | excess in ethanol, heat in sealed tube | mixture of amines (mainly primary) | unchanged |
| halogenoalkane | primary amine in ethanol, heat in sealed tube | secondary amine | joins two chains |
| nitrile | in dry ether, or /Ni, or Na/ethanol | primary amine | unchanged (but a nitrile made from + has one extra C) |
| amide | in dry ether | primary amine (N-substituted amides give secondary amines) | unchanged |
12.2Basicity of aminesOften examined
In amines the nitrogen atom is sp^3 hybridised. Three sp^3 orbitals form \sigma bonds to H or C atoms, and the fourth holds a lone pair. The shape is nearly tetrahedral; counting only the atoms it is trigonal pyramidal (bond angles about 107^\circ), just like ammonia.
The lone pair makes amines bases: it accepts a proton (\ce{H+}), exactly as in ammonia. When an amine dissolves in water, the lone pair takes a proton from a water molecule, forming an alkylammonium ion and hydroxide ions. The \ce{OH-} ions make the solution alkaline (it turns red litmus blue). Alkylamines are stronger bases than ammonia.
ethylamine gives the ethylammonium ion
K_b: base dissociation constant (\mathrm{mol\,dm^{-3}}). A larger K_b, or a **lower \mathrm{p}K_b, means a stronger base**.
Amines also neutralise acids, forming salts. These salts are ionic, crystalline and soluble in water. A strong alkali releases the free amine again.
ethylammonium chloride
12.2.1Relative basicities of ammonia, ethylamine and phenylamineOften examined
The strengths of weak bases are compared with their \mathrm{p}K_b values. The lower the \mathrm{p}K_b, the stronger the base.
| Base | Formula | \mathrm{p}K_b | K_b\,/\,\mathrm{mol\,dm^{-3}} |
|---|---|---|---|
| ethylamine | \ce{CH3CH2NH2} | 3.27 | 5.4\times10^{-4} |
| ammonia | \ce{NH3} | 4.75 | 1.8\times10^{-5} |
| phenylamine | \ce{C6H5NH2} | 9.36 | 4.4\times10^{-10} |
| Base | ethylamine | ammonia | phenylamine |
|---|---|---|---|
| Formula | \ce{CH3CH2NH2} | \ce{NH3} | \ce{C6H5NH2} |
| \mathrm{p}K_b | 3.27 | 4.75 | 9.36 |
| K_b\,/\,\mathrm{mol\,dm^{-3}} | 5.4\times10^{-4} | 1.8\times10^{-5} | 4.4\times10^{-10} |
Two factors decide the strength of a base
- Availability of the lone pair: how easily the nitrogen lone pair can capture an \ce{H+} ion. More electron density on nitrogen means a stronger base.
- Stability of the ion formed: how stable the positive ion is after it has received the \ce{H+} ion. A more stable cation means a stronger base.
Ethylamine is a stronger base than ammonia
The ethyl group is electron-donating (positive inductive effect, +I). It pushes electron density onto the nitrogen, so the lone pair is more electron-rich and attracts \ce{H+} more strongly. In the ethylammonium ion the ethyl group also partly cancels the positive charge on nitrogen, spreading it out, so this ion is more stable than the simple ammonium ion. Both factors make ethylamine the stronger base.
Phenylamine is a much weaker base than ammonia
In phenylamine the lone pair on nitrogen overlaps with the \pi electrons of the benzene ring and is delocalised over the ring. It is therefore much less available to bond with a proton, and the electron density around the nitrogen atom is much lower than in ammonia. In addition, when phenylamine does accept a proton, this delocalisation is lost, so the phenylammonium ion gets no extra stability.
Basicity in the gas phase and in water (beyond the book)
In the gas phase there are no solvent molecules, so only the inductive effect matters. Each extra alkyl group pushes more electron density onto nitrogen, and the order simply follows the number of alkyl groups:
In water a third factor appears: the cation formed is stabilised by hydrogen bonding with water molecules (solvation). \ce{RNH3+} has three \ce{N-H} bonds that can hydrogen-bond to water, \ce{R2NH2+} has two, and \ce{R3NH+} only one. Three bulky alkyl groups also crowd the nitrogen and hinder solvation. So the tertiary amine's cation is poorly stabilised in water, and the order changes:
| Base | \mathrm{p}K_b in water | N-H bonds in the cation | Gas-phase order |
|---|---|---|---|
| \ce{NH3} | 4.75 | 4 | weakest |
| \ce{CH3NH2} | 3.36 | 3 | 3rd |
| \ce{(CH3)2NH} | 3.27 | 2 | 2nd |
| \ce{(CH3)3N} | 4.20 | 1 | strongest |
12.3Formation of nitriles and hydroxynitrilesOften examined
1. From halogenoalkanes and KCN
Nitriles (alkyl cyanides) contain the \ce{-C#N} group. They are made by heating a halogenoalkane under reflux with potassium cyanide dissolved in ethanol. The cyanide ion is a nucleophile: it attacks the \delta+ carbon and the halide ion leaves (nucleophilic substitution). Ethanol is used as the solvent because in water the hydroxide ions would give an alcohol instead.
ethanenitrile (book: cyanomethane)
propanenitrile (book: cyanoethane)
A nitrile is named from the total number of carbon atoms including the carbon of \ce{-C#N}. So \ce{CH3CN} is ethanenitrile and \ce{CH3CH2CN} is propanenitrile.
2. Hydroxynitriles from aldehydes and ketones
Aldehydes and ketones add hydrogen cyanide across the \ce{C=O} double bond, forming hydroxynitriles (also called cyanohydrins). HCN is a very poisonous gas, so it is not used directly: the aldehyde or ketone is mixed with a solution of \ce{KCN} (or \ce{NaCN}) in water containing a little acid. The acid produces HCN in the mixture, but some free \ce{CN-} ions remain, and these catalyse the reaction.
formaldehyde cyanohydrin (2-hydroxyethanenitrile)
acetaldehyde cyanohydrin (2-hydroxypropanenitrile)
acetone cyanohydrin (2-hydroxy-2-methylpropanenitrile)
This is a nucleophilic addition. The cyanide ion attacks the \delta+ carbonyl carbon, the \ce{C=O} \pi electrons move onto oxygen, and the alkoxide ion formed takes a proton from HCN, regenerating \ce{CN-}:
- The \ce{CN-} ion attacks the carbonyl carbon.\ce{CH3CHO + CN- -> CH3CH(O^-)CN}
- The alkoxide ion takes \ce{H+} from HCN; \ce{CN-} is regenerated (catalyst).\ce{CH3CH(O^-)CN + HCN -> CH3CH(OH)CN + CN-}
Again the carbon chain grows by one carbon, so this reaction is also used in organic synthesis to increase chain length.
12.4Hydrolysis of nitrilesOften examined
Nitriles are hydrolysed by heating under reflux with dilute acid or dilute alkali. The \ce{-C#N} group becomes \ce{-COOH} (or its salt) and the nitrogen leaves as ammonia or an ammonium salt. The reaction passes through an amide:
Acid hydrolysis
When a nitrile is heated under reflux with dilute hydrochloric acid or dilute sulphuric acid, a carboxylic acid is formed directly. The ammonia produced reacts with the acid to give an ammonium salt.
ethanenitrile gives ethanoic acid
Alkaline hydrolysis followed by acidification
When a nitrile is heated under reflux with dilute sodium hydroxide solution, the sodium salt of the carboxylic acid is formed and ammonia gas is given off (it turns damp red litmus blue). Acidifying with dilute hydrochloric acid then gives the free carboxylic acid.
| Acid hydrolysis | Alkaline hydrolysis | |
|---|---|---|
| Reagent | dilute \ce{HCl} or \ce{H2SO4}, heat under reflux | dilute \ce{NaOH}, heat under reflux |
| Nitrogen ends up as | \ce{NH4+} salt (stays in solution) | \ce{NH3} gas (given off) |
| Organic product | carboxylic acid | carboxylate salt; acid only after adding dilute HCl |
12.5 (a)Reaction of phenylamine with bromine waterOften examined
When bromine water is added to an aqueous solution of phenylamine at room temperature, the reddish-brown colour of bromine is decolourised at once and a white precipitate of 2,4,6-tribromophenylamine forms. No catalyst is needed.
The \ce{-NH2} group makes the ring very reactive. The nitrogen lone pair is delocalised into the ring and raises the electron density, especially at positions 2, 4 and 6 (see the resonance structures in 12.2.1). The ring is so electron-rich that it polarises bromine molecules itself and is attacked by them (electrophilic substitution) at all three positions.
Benzene, by contrast, reacts with bromine only in the presence of a halogen carrier such as \ce{FeBr3}, and gives just one substitution product (bromobenzene). Phenol behaves like phenylamine and gives 2,4,6-tribromophenol with bromine water.
12.5 (b)Diazotisation: preparing benzenediazonium chlorideOften examined
Phenylamine reacts with nitrous acid, \ce{HNO2}, and dilute hydrochloric acid at a low temperature to give benzenediazonium chloride (also called phenyl diazonium chloride). This reaction is called diazotisation.
Nitrous acid is unstable, so it is made in the mixture from sodium nitrite and hydrochloric acid:
overall
Procedure
- Phenylamine is dissolved in excess dilute hydrochloric acid and the solution is cooled in ice to below 5^\circ\mathrm{C}.
- A solution of sodium (or potassium) nitrite is also cooled in ice.
- The ice-cold nitrite solution is added slowly, with stirring, to the phenylamine solution. The temperature must never go above 5^\circ\mathrm{C}.
- The solution of benzenediazonium chloride formed is used at once; it is not stored or dried.
Why the mixture is kept so cold
- Diazonium salts are unstable. Above about 10^\circ\mathrm{C} the diazonium ion reacts rapidly with water, losing nitrogen gas and forming phenol. The desired product would be lost.
- Nitrous acid decomposes on warming, so it would be lost before it could react.
- The reaction gives out heat, so the nitrite is added slowly to stop the temperature rising.
- Dry diazonium salts can explode, which is why they are kept in cold solution and used immediately.
Benzenediazonium ions are stable enough to use at 0 to 5^\circ\mathrm{C} because the positive charge is partly delocalised into the benzene ring. Diazonium ions made from alkylamines (such as ethylamine) have no ring to stabilise them and decompose immediately, even in the cold, giving off nitrogen.
12.6Reactions of benzenediazonium chloride and azo dyesOften examined
1. Reaction with water: phenol
When an aqueous solution of benzenediazonium chloride is warmed (to about 50^\circ\mathrm{C}), it decomposes: bubbles of nitrogen gas are given off and phenol is formed. This is the way to convert phenylamine into phenol.
2. Coupling with phenol: azo compounds
Phenol is dissolved in sodium hydroxide solution to form sodium phenoxide, and the solution is cooled in ice. When it is mixed with ice-cold benzenediazonium chloride solution, a coupling reaction takes place between the phenoxide ion and the diazonium ion. A yellow-orange solution or precipitate of 4-hydroxyazobenzene forms.
sodium phenoxide
4-hydroxyazobenzene, 4-(phenylazo)phenol
The diazonium ion is a weak electrophile. It can only attack a strongly activated ring, such as phenoxide, and it substitutes at the 4-position (para to \ce{-O-}). The alkali converts phenol into phenoxide, whose ring is even more electron-rich. The cold keeps the diazonium ion from decomposing.
The azo group and azo dyes
The product contains the azo group, \ce{-N=N-}, which links two benzene rings through a nitrogen bridge. Compounds containing this group are called azo compounds. The azo group joins the two rings into one long delocalised system that absorbs visible light, so azo compounds are strongly coloured and are used as azo dyes. Azo dyes are the largest class of dyes: the book puts them at more than 60% of all dyes (about 70% of industrial dyes).
Other azo dyes by the same route
Changing the coupling partner changes the colour. When ice-cold benzenediazonium chloride is shaken with phenylamine, a yellow solid dye, aniline yellow (4-aminoazobenzene), is formed.
Coupling with naphthalen-2-ol (2-naphthol) in alkali gives an orange-red dye; methyl orange, the acid-base indicator, is also an azo dye.
Diazonium salts in synthesis (beyond the book)
The \ce{-N2+} group leaves very easily as nitrogen gas, one of the most stable molecules. So it can be replaced by many groups that cannot be put onto a benzene ring directly. This makes diazonium salts very useful in organic synthesis.
| Reagent added to the diazonium salt | Product |
|---|---|
| water, warm | phenol, \ce{C6H5OH} |
| \ce{CuCl} in HCl | chlorobenzene, \ce{C6H5Cl} |
| \ce{CuBr} in HBr | bromobenzene, \ce{C6H5Br} |
| \ce{CuCN} in KCN | benzonitrile, \ce{C6H5CN} (then hydrolysed to benzoic acid) |
| \ce{KI(aq)} | iodobenzene, \ce{C6H5I} |
| \ce{H3PO2} (phosphinic acid) | benzene, \ce{C6H6} |
| phenol or phenylamine, cold (coupling) | azo dyes |
12.7Preparation of amides
Amides contain the group \ce{-CONH2} (or \ce{-CONHR}, \ce{-CONR2}). They are made from acyl chlorides by the nucleophilic addition-elimination mechanism of Unit 11.
1. Acyl chloride with ammonia
Acyl chlorides react with ammonia at room temperature to give amides. The hydrogen chloride produced reacts with excess ammonia to give ammonium chloride.
ethanamide
2. Acyl chloride with a primary amine
Primary amines react in the same way at room temperature to give N-substituted amides. The HCl reacts with excess amine to give an alkylammonium salt.
methanamine (methylamine) gives N-methylethanamide
12.7.1Reactions of amidesOften examined
1. Reduction to amines
When an amide is treated with lithium aluminium hydride, \ce{LiAlH4}, the \ce{C=O} group is reduced to \ce{CH2} and a primary amine is formed. The carbon chain stays the same length.
the book prints 2[H]; 4[H] is needed to balance
2. Hydrolysis
Amides are hydrolysed by heating under reflux with dilute acid or dilute alkali. The \ce{C-N} bond breaks.
(a) Acid hydrolysis
Heating with dilute hydrochloric acid or dilute sulphuric acid gives the carboxylic acid and an ammonium salt.
ethanamide gives ethanoic acid
(b) Alkaline hydrolysis
Heating with dilute sodium hydroxide solution gives the sodium salt of the carboxylic acid and ammonia gas. The salt gives the free acid on acidification with dilute hydrochloric acid.
12.7.2Why amides are much weaker bases than aminesOften examined
Amides contain an \ce{-NH2} group, but they are much weaker bases than amines. Aqueous solutions of amides are practically neutral to litmus, and amides do not form stable salts with dilute acids.
1. Delocalisation (resonance). The lone pair on the nitrogen of an amide is delocalised onto the carbonyl group. Part of the electron density moves onto the electronegative oxygen, and the \ce{C-N} bond gets partial double-bond character. The lone pair is no longer free to accept a proton.
2. Inductive effect. The carbonyl group is strongly electron-withdrawing. It pulls electrons away from the nitrogen, lowering the electron density there still further.
In amines neither effect exists: the lone pair on nitrogen is not delocalised, and alkyl groups push electron density onto the nitrogen (+I effect). So amines attract protons strongly. If an amide is protonated at all (only by very strong acids), the proton goes onto the oxygen, not onto the nitrogen.
| Ethylamine, \ce{CH3CH2NH2} | Ethanamide, \ce{CH3CONH2} | |
|---|---|---|
| Group next to N | ethyl (+I, pushes electrons in) | \ce{C=O} (pulls electrons out) |
| Nitrogen lone pair | localised, available | delocalised onto O |
| \mathrm{p}K_b | 3.3 | about 14.5 |
| Aqueous solution | alkaline | neutral |
| With dilute \ce{HCl} | forms a salt | no salt |
12.8Amino acids
Compounds that contain an amino group (\ce{-NH2}) and a carboxylic acid group (\ce{-COOH}) are called amino acids. So an amino acid has two functional groups: a basic one (\ce{-NH2}) and an acidic one (\ce{-COOH}).
Amino acids are the building blocks of proteins. Twenty different amino acids are used in protein synthesis. According to the book, the body can make ten of them; these are non-essential amino acids. The other ten are essential amino acids: the body cannot make them, so they must be present in the diet.
General formula: the central carbon carries an amino group, a carboxylic acid group, a hydrogen atom and a side chain R, which is different in each amino acid.
In the amino acids of proteins the amino group is on the carbon atom **next to the \ce{-COOH} group. They are called 2-amino acids or \alpha-amino acids**.
Except in glycine, the central carbon carries four different groups, so these amino acids are chiral and optically active.
12.8.1Zwitterions and the acid-base properties of amino acidsOften examined
An amino acid has both a basic amine group and an acidic carboxylic acid group in the same molecule. A hydrogen ion moves internally from the \ce{-COOH} group to the \ce{-NH2} group. This leaves an ion with a positive charge and a negative charge, called a zwitterion (from the German for 'double ion').
glycine: neutral form and zwitterion
A zwitterion has no overall electrical charge, but it contains separate parts that are positively and negatively charged.
Physical properties
Amino acids exist as zwitterions even in the solid state. The forces between neighbouring zwitterions are strong ionic attractions, like those in a salt. These need a lot of energy to break, so amino acids are crystalline solids with high melting points (glycine decomposes at about 233^\circ\mathrm{C}). For the same reason they dissolve in water but not in non-polar solvents.
Acid-base (amphoteric) properties
The zwitterion contains an acidic site (\ce{-NH3+}, which can donate \ce{H+}) and a basic site (\ce{-COO-}, which can accept \ce{H+}). So amino acids react with both acids and bases; they are amphoteric.
in acid (low pH): the basic site accepts a proton, giving a positive ion
in alkali (high pH): the acidic site loses a proton, giving a negative ion
The pH at which an amino acid is present as the zwitterion, with no net charge, is its isoelectric point (pI). For glycine it is about 6.0. Because amino acids can remove both \ce{H+} and \ce{OH-}, their solutions resist changes in pH (they act as buffers).
| pH of solution | Main form of glycine | Net charge | In an electric field |
|---|---|---|---|
| low (acidic, below pI) | \ce{H3N+CH2COOH} | +1 | moves to cathode (−) |
| at pI (about 6) | \ce{H3N+CH2COO-} | 0 | does not move |
| high (alkaline, above pI) | \ce{H2NCH2COO-} | −1 | moves to anode (+) |
12.8.2Formation of the peptide bondOften examined
Amino acid molecules join through the amino group (\ce{-NH2}) of one molecule and the carboxyl group (\ce{-COOH}) of another. A molecule of water is eliminated (a condensation reaction), and the two units are joined by an amide linkage \ce{-CO-NH-}, called a peptide bond. The product of two amino acids is a dipeptide.
For example, glycine and alanine can join in two different ways, giving two different dipeptides:
Gly-Ala
A dipeptide still has a free amino group at one end and a free carboxyl group at the other. Each can react with more amino acids. A dipeptide joined to one more amino acid is a tripeptide (two peptide bonds, two water molecules eliminated). In the same way thousands of amino acid units join into a giant protein molecule. A chain of n amino acids contains n-1 peptide bonds.
The reverse reaction, hydrolysis, breaks peptide bonds and gives back the amino acids. It happens when a protein is boiled with hydrochloric acid, and in digestion, where enzymes (proteases) catalyse it.
12.8.3Electrophoresis of amino acids and dipeptidesOften examined
Electrophoresis is a technique that separates charged molecules, such as amino acids and peptides, using an electric field. A strip of paper or gel is soaked in a buffer of known pH and placed between two electrodes. A spot of the mixture is placed at the centre and a voltage is applied. Each species moves according to its charge. Afterwards the strip is dried and sprayed with ninhydrin, which shows the amino acids as coloured spots.
The pH of the buffer controls the charge of each amino acid:
- At low pH (below its pI) an amino acid is protonated (\ce{-NH3+} and \ce{-COOH}), carries a positive charge and moves towards the cathode (negative electrode).
- At high pH (above its pI) it is deprotonated (\ce{-NH2} and \ce{-COO-}), carries a negative charge and moves towards the anode (positive electrode).
- At its isoelectric point it is a zwitterion with no net charge and does not move.
The speed of movement depends on the size of the charge (a larger charge moves faster) and on the size (mass) of the molecule (a smaller molecule moves faster). Different amino acids have different pI values and masses, so they end up in different places and are separated.
| Amino acid (pI) | pH 3 | pH 6 | pH 11 |
|---|---|---|---|
| glycine (6.0) | positive: moves slowly to cathode | zwitterion: stays at start | negative: moves to anode |
| lysine (9.7) | positive (larger charge): moves farther to cathode | positive: moves to cathode | slightly negative: moves slowly to anode |
| aspartic acid (2.8) | almost neutral: stays near start | negative: moves to anode | doubly negative: moves fastest to anode |
Dipeptides behave in the same way. Their charge depends on the free \ce{-NH3+} and \ce{-COO-} groups at the chain ends (and any charged side chains), so it also changes with pH. A dipeptide is heavier than the amino acids it is made from, so with the same charge it moves more slowly.
Formula sheet
Key terms
- Amine
- A derivative of ammonia in which one or more H atoms are replaced by alkyl or aryl groups.
- Primary, secondary, tertiary amine
- An amine with one (\ce{RNH2}), two (\ce{R2NH}) or three (\ce{R3N}) carbon atoms bonded to the nitrogen.
- Quaternary ammonium salt
- An ionic compound \ce{R4N+X-} in which nitrogen is bonded to four carbon atoms and has no lone pair.
- Phenylamine (aniline)
- \ce{C6H5NH2}, the simplest aromatic amine.
- Nitrile
- A compound containing the \ce{-C#N} group, for example ethanenitrile \ce{CH3CN}.
- Hydroxynitrile (cyanohydrin)
- A compound with \ce{-OH} and \ce{-CN} on the same carbon, formed by adding HCN to an aldehyde or ketone.
- Base (Brønsted-Lowry)
- A proton (\ce{H+}) acceptor; amines accept protons with the lone pair on nitrogen.
- Kb and pKb
- K_b is the base dissociation constant; \mathrm{p}K_b=-\log_{10}K_b. The lower the \mathrm{p}K_b, the stronger the base.
- Positive inductive effect (+I)
- Electron donation through \sigma bonds by groups such as alkyl groups; it increases the electron density on nitrogen.
- Delocalisation
- Spreading of a lone pair or charge over several atoms, for example the nitrogen lone pair of phenylamine into the benzene ring.
- Solvation
- Stabilisation of an ion by surrounding solvent molecules; alkylammonium ions are stabilised by hydrogen bonds to water.
- Nitrogen inversion
- Rapid turning inside out of an amine's pyramidal shape, which stops amines with three different groups from being optically active.
- Amide
- A compound containing \ce{-CONH2} (or \ce{-CONHR}, \ce{-CONR2}); a very weak base.
- N-substituted amide
- An amide in which an H atom on nitrogen is replaced by an alkyl group, for example N-methylethanamide \ce{CH3CONHCH3}.
- Diazotisation
- The reaction of a primary aromatic amine with nitrous acid and HCl at 0 to 5^\circ\mathrm{C} to form a diazonium salt.
- Diazonium salt
- A salt containing the \ce{Ar-N#N+} ion, such as benzenediazonium chloride; unstable above about 10^\circ\mathrm{C}.
- Coupling reaction
- The reaction of a diazonium ion with an activated aromatic compound (phenol or phenylamine) to form an azo compound.
- Azo group
- The group \ce{-N=N-} that links two aromatic rings in azo compounds.
- Azo dye
- A strongly coloured azo compound used as a dye, for example 4-hydroxyazobenzene and aniline yellow.
- Amino acid
- A compound containing both an amino group (\ce{-NH2}) and a carboxylic acid group (\ce{-COOH}).
- Alpha-amino acid (2-amino acid)
- An amino acid in which the amino group is on the carbon next to the \ce{-COOH} group.
- Essential amino acid
- An amino acid the body cannot make, so it must be obtained from the diet.
- Zwitterion
- An ion that carries both a positive and a negative charge but has no overall charge, for example \ce{H3N+CH2COO-}.
- Amphoteric
- Able to react both as an acid and as a base; amino acids are amphoteric.
- Isoelectric point (pI)
- The pH at which an amino acid exists as a zwitterion with no net charge and does not move in an electric field.
- Peptide bond
- The amide linkage \ce{-CO-NH-} that joins two amino acid units, formed with loss of water.
- Dipeptide, tripeptide
- Molecules formed from two or three amino acids joined by one or two peptide bonds.
- Electrophoresis
- A technique that separates charged molecules such as amino acids and peptides by their movement in an electric field.
Multiple choice questionsp. 212–213
- A\ce{NH3} in ethanol, heated under pressureAnswer
- B\ce{H2SO4} in water, room temperature
- C\ce{LiAlH4} in dry ether, reflux
- D\ce{KOH} in ethanol, heated under pressure
Ammonia is the nucleophile that replaces the halogen: \ce{C2H5Br + NH3 -> C2H5NH2 + HBr}. It is dissolved in ethanol and heated in a sealed tube (under pressure) because ammonia is a gas. \ce{KOH} in ethanol causes elimination to an alkene, and \ce{LiAlH4} reduces nitriles and amides, not halogenoalkanes, to amines.
- A\ce{H2O}, \ce{H2SO4}, heat
- B\ce{HCN}, \ce{KCN} as a catalyst, heatAnswer
- C\ce{NH3} in ethanol, heated under pressure
- D\ce{Br2}, light, room temperature
HCN adds across the \ce{C=O} bond by nucleophilic addition; \ce{KCN} supplies the \ce{CN-} nucleophile that starts the reaction, for example \ce{CH3CHO + HCN -> CH3CH(OH)CN}.
- AReaction with ammonia in ethanol
- BReaction with primary amines in ethanolAnswer
- CReaction with \ce{LiAlH4}
- DReaction with HCN and KCN
A primary amine is a nucleophile like ammonia. Heated with a halogenoalkane in ethanol in a sealed tube it gives a secondary amine: \ce{C2H5Br + C2H5NH2 -> (C2H5)2NH + HBr}. Ammonia gives mainly a primary amine.
- A\ce{H2O}, HCl, reflux
- B\ce{H2}/Pt, room temperature
- C\ce{H2}/Ni or \ce{LiAlH4}Answer
- D\ce{Br2}, room temperature
Nitriles are reduced to primary amines by \ce{LiAlH4} in dry ether or by hydrogen over a heated nickel catalyst: \ce{CH3CN + 4[H] -> CH3CH2NH2}. Water and HCl under reflux hydrolyse a nitrile to a carboxylic acid instead.
- AAlcohol
- BKetone
- CCarboxylic acidAnswer
- DAldehyde
Heating with dilute acid converts \ce{-C#N} into \ce{-COOH} and the nitrogen ends up as an ammonium salt: \ce{CH3CN + 2H2O + HCl -> CH3COOH + NH4Cl}.
- A\ce{R1-N=N-R2}Answer
- B\ce{R1-C#N-R2}
- C\ce{R1-NH2-R2}
- D\ce{R1-O-R2}
The azo group is two nitrogen atoms joined by a double bond, \ce{-N=N-}, linking two groups (usually two benzene rings). Option B is not a real structure; option D is an ether.
- APhenol
- BPhenylamine bromide
- C2,4,6-tribromophenylamineAnswer
- DAn azo compound
The \ce{-NH2} group activates positions 2, 4 and 6 so strongly that all three are substituted at once, without a catalyst. A white precipitate forms: \ce{C6H5NH2 + 3Br2 -> C6H2Br3NH2 + 3HBr}.
- AEthylamine > Aqueous ammonia > PhenylamineAnswer
- BPhenylamine > Ethylamine > Aqueous ammonia
- CAqueous ammonia > Ethylamine > Phenylamine
- DAqueous ammonia > Phenylamine > Ethylamine
The ethyl group pushes electrons onto nitrogen (+I), so ethylamine (\mathrm{p}K_b 3.27) is stronger than ammonia (4.75). In phenylamine the lone pair is delocalised into the ring, so it is the weakest (\mathrm{p}K_b 9.36).
- AFormation of phenylhydrazine
- BFormation of an azo compoundAnswer
- CFormation of a nitro compound
- DFormation of an ester
This is a coupling reaction. The diazonium ion attacks the 4-position of the phenoxide ion and gives the yellow-orange azo compound 4-hydroxyazobenzene, which contains \ce{-N=N-}.
- AProvide structural support
- BStore energy
- CLink amino acidsAnswer
- DBind with DNA
A peptide bond, \ce{-CO-NH-}, joins the carboxyl group of one amino acid to the amino group of the next. Chains of amino acids linked in this way make up every protein.
- AAmides
- BCarboxylic acidsAnswer
- CAlcohols
- DAmines
An amide is formed first, but under reflux with dilute acid it is hydrolysed further, so the final product is the carboxylic acid (plus an ammonium salt). Amines come from reduction, not hydrolysis.
- ATrihalogenated productAnswer
- BMonohalogenated product
- CDihalogenated product
- DNo reaction
Three bromine atoms enter the ring at positions 2, 4 and 6, giving 2,4,6-tribromophenylamine. Benzene, by contrast, needs a \ce{FeBr3} catalyst and gives only a monobromo product.
Short answer questionsp. 213
Reagent: potassium cyanide, \ce{KCN}, dissolved in ethanol (not water). Condition: the mixture is heated under reflux.
The cyanide ion is a nucleophile. It attacks the \delta+ carbon of the \ce{C-X} bond and the halide ion leaves (nucleophilic substitution). Ethanol is used as the solvent because in water the \ce{OH-} ions formed would compete and give an alcohol. Heating under reflux speeds up the slow reaction without losing the volatile liquids.
bromoethane gives propanenitrile
The product has one more carbon atom than the halogenoalkane, so this reaction is used to lengthen a carbon chain.
Amides are hydrolysed by heating under reflux with dilute acid or dilute alkali. Water breaks the \ce{C-N} bond of the \ce{-CONH2} group.
Acid hydrolysis: with dilute HCl (or \ce{H2SO4}) the products are the carboxylic acid and an ammonium salt.
Alkaline hydrolysis: with dilute \ce{NaOH} the products are the sodium salt of the acid and ammonia gas, which turns damp red litmus blue. Adding dilute HCl then frees the carboxylic acid.
Final product: a carboxylic acid (ethanoic acid from ethanamide). In alkali it is first obtained as its salt, and the acid is released on acidification.
This reaction is called diazotisation. Nitrous acid is unstable, so it is made in the mixture from sodium nitrite and dilute hydrochloric acid. Ice-cold \ce{NaNO2} solution is added slowly to phenylamine dissolved in dilute HCl, keeping the temperature between 0 and 5^\circ\mathrm{C}.
Major product: benzenediazonium chloride, \ce{C6H5N2+Cl-}. The low temperature is essential because the diazonium salt decomposes above about 10^\circ\mathrm{C}, giving phenol and nitrogen gas. The solution is used at once to make phenol or azo dyes.
An amino acid has an acidic \ce{-COOH} group and a basic \ce{-NH2} group in the same molecule. An \ce{H+} ion moves from the \ce{-COOH} group to the \ce{-NH2} group, forming a zwitterion: an ion with a positive and a negative part but no overall charge.
glycine
The zwitterion is amphoteric. Its \ce{-COO-} group accepts \ce{H+} from acids, and its \ce{-NH3+} group gives \ce{H+} to bases:
So amino acids are positive ions in acid, negative ions in alkali, and zwitterions at their isoelectric point. The ionic attractions between zwitterions give amino acids high melting points.
Structural aspect: in an amide the nitrogen is bonded directly to a carbonyl group, \ce{C=O}; in an amine it is bonded to alkyl groups or H.
The lone pair on the amide nitrogen is delocalised onto the carbonyl group and the electronegative oxygen (resonance), so it is not available to accept a proton. The \ce{C=O} group is also electron-withdrawing and lowers the electron density on nitrogen. In an amine the lone pair is localised, and alkyl groups push electrons onto nitrogen (+I), so it accepts protons easily.
So amide solutions are neutral, while amine solutions are alkaline (\mathrm{p}K_b about 14.5 for ethanamide, 3.3 for ethylamine).
All three are bases because the lone pair on nitrogen accepts a proton. Their \mathrm{p}K_b values (lower means stronger) give the order:
Ethylamine > ammonia: the ethyl group is electron-donating (+I). It increases the electron density on nitrogen, so the lone pair attracts \ce{H+} more strongly, and it spreads the positive charge of the \ce{CH3CH2NH3+} ion, making it more stable.
Ammonia > phenylamine: in phenylamine the nitrogen lone pair is delocalised into the benzene ring, so it is much less available to accept a proton.
Conditions: the nitrile is heated under reflux with dilute hydrochloric acid (or dilute sulphuric acid).
Step 1: water adds across the \ce{C#N} bond and the nitrile is converted into an amide.
Step 2: the amide is hydrolysed further to the carboxylic acid. The ammonia released reacts with the acid to form an ammonium salt.
Overall: \ce{CH3CN + 2H2O + HCl -> CH3COOH + NH4Cl}. The carboxylic acid is then separated from the mixture by distillation.
Note. The book prints this and the next question as sub-items (i) and (ii) under Q.vi, although they are separate questions; the book's numbering is kept.
Amides are hydrolysed by heating under reflux with dilute acid or dilute alkali. Water breaks the \ce{C-N} bond of the \ce{-CONH2} group.
Acid hydrolysis: with dilute HCl (or \ce{H2SO4}) the products are the carboxylic acid and an ammonium salt.
Alkaline hydrolysis: with dilute \ce{NaOH} the products are the sodium salt of the acid and ammonia gas, which turns damp red litmus blue. Adding dilute HCl then frees the carboxylic acid.
In both cases the \ce{C-N} bond is broken; the difference is that acid gives the free acid and an ammonium salt, while alkali gives the carboxylate salt and ammonia gas.
Note. This repeats short question ii.
In electrophoresis a charged species moves towards the electrode of opposite charge. Below its isoelectric point (pI) an amino acid is positive and moves to the cathode; above its pI it is negative and moves to the anode. Take a mixture of glycine (pI 6.0), lysine (pI 9.7) and aspartic acid (pI 2.8):
| Amino acid | At pH 3 | At pH 11 |
|---|---|---|
| glycine | positive (\ce{H3N+CH2COOH}): moves to cathode | negative (\ce{H2NCH2COO-}): moves to anode |
| lysine | positive, larger charge: moves farthest to cathode | slightly negative: moves slowly to anode |
| aspartic acid | almost neutral (near its pI): stays near the start | charge 2−: moves fastest to anode |
So at pH 3 most amino acids move to the cathode, and at pH 11 all move to the anode. A larger charge and a smaller size give faster movement, so the amino acids separate.
Both nitriles and amides are reduced by lithium aluminium hydride in dry ether to primary amines.
nitrile: four H atoms add across the triple bond
amide: \ce{C=O} is reduced to \ce{CH2} and oxygen leaves as water
| Nitrile | Amide | |
|---|---|---|
| Group reduced | \ce{-C#N} to \ce{-CH2NH2} | \ce{-CONH2} to \ce{-CH2NH2} |
| Oxygen removed | none present | yes, as water |
| Other reducing agent | \ce{H2}/Ni also works | only \ce{LiAlH4} |
Both keep the same number of carbon atoms, so ethanenitrile and ethanamide give the same amine, ethylamine.
Note. The book prints this and the next question as sub-items (i) and (ii) under Q.vii; the book's numbering is kept.
Diazonium salts, such as benzenediazonium chloride, are very useful intermediates because the \ce{-N2+} group leaves easily as nitrogen gas, a very stable molecule. It can therefore be replaced by groups that cannot be put onto a benzene ring directly.
- Warming with water gives phenol: \ce{C6H5N2+Cl- + H2O -> C6H5OH + N2 + HCl}.
- With \ce{CuCl}, \ce{CuBr}, \ce{CuCN} or \ce{KI} it gives chlorobenzene, bromobenzene, benzonitrile or iodobenzene.
- Coupling with phenol (in \ce{NaOH}) or phenylamine gives coloured azo dyes containing \ce{-N=N-}, used for fabrics, food colours and indicators such as methyl orange.
So one starting material, phenylamine, leads to many aromatic products.
Long answer questionsp. 214
Introduction
A nitrile contains the \ce{-C#N} group. When it is heated with water in the presence of an acid or an alkali, the \ce{C#N} group is converted into a \ce{-COOH} group and the nitrogen is removed as ammonia (or an ammonium salt). The reaction takes place in two stages: the nitrile first gives an amide, and the amide is then hydrolysed to the carboxylic acid.
Hydrolysis with dilute acid
- Conditions: heat the nitrile under reflux with dilute hydrochloric acid or dilute sulphuric acid.
- Stage 1: water adds across the triple bond, giving the amide.
- Stage 2: the amide is hydrolysed to the carboxylic acid. The ammonia formed reacts at once with the excess acid, so the nitrogen stays in solution as an ammonium salt.
- The carboxylic acid is obtained directly and is separated by distillation.
ethanenitrile gives ethanoic acid
Hydrolysis with dilute alkali followed by acidification
- Conditions: heat the nitrile under reflux with dilute sodium hydroxide solution.
- The products are the sodium salt of the carboxylic acid and ammonia gas. Ammonia can be detected because it turns damp red litmus paper blue.
- The salt is not the free acid. The solution is cooled and acidified with dilute HCl or \ce{H2SO4}, which converts the carboxylate ion into the carboxylic acid (a strong acid displaces a weak acid from its salt).
Comparison
| Dilute acid | Dilute alkali, then acid | |
|---|---|---|
| Reagent | dilute \ce{HCl} or \ce{H2SO4} | dilute \ce{NaOH}, then dilute \ce{HCl} |
| Nitrogen ends up as | \ce{NH4Cl} in solution | \ce{NH3} gas |
| Organic product before work-up | carboxylic acid | carboxylate salt |
Final product and its use
The final product in both methods is a carboxylic acid. Because a nitrile is made from a halogenoalkane and \ce{KCN}, the sequence halogenoalkane \to nitrile \to carboxylic acid adds one carbon atom to the chain. For example, bromoethane (2 carbons) gives propanoic acid (3 carbons):
Why amines and ammonia are bases
Ammonia, ethylamine and phenylamine each have a lone pair on the nitrogen atom. The lone pair accepts a proton from water, forming a positive ion and hydroxide ions, so their solutions are alkaline.
The strength of a weak base is measured by \mathrm{p}K_b: the lower the \mathrm{p}K_b, the stronger the base.
| Base | \mathrm{p}K_b |
|---|---|
| ethylamine, \ce{CH3CH2NH2} | 3.27 |
| ammonia, \ce{NH3} | 4.75 |
| phenylamine, \ce{C6H5NH2} | 9.36 |
Factors that decide basic strength
- Availability of the lone pair on nitrogen. The more electron density on nitrogen, the more strongly it attracts \ce{H+}. Electron-donating groups (+I) increase it; delocalisation of the lone pair into a ring decreases it.
- Stability of the cation formed. The more the positive charge of the ion is spread out (and stabilised by the solvent), the more readily the base accepts \ce{H+}.
Ethylamine is stronger than ammonia
The ethyl group is electron-donating (positive inductive effect). It pushes electron density onto the nitrogen, so the lone pair is more available for a proton. The ethyl group also spreads the positive charge of \ce{CH3CH2NH3+}, so this ion is more stable than \ce{NH4+}. Both factors favour ethylamine.
Phenylamine is much weaker than ammonia
In phenylamine the lone pair on nitrogen overlaps with the delocalised \pi electrons of the benzene ring. It is spread over the ring (resonance), so the electron density on nitrogen falls and the lone pair is much less available to bond to \ce{H+}.
When phenylamine is protonated, the lone pair is used to bond to \ce{H+} and this resonance stabilisation is lost, so the reaction is unfavourable. The benzene ring is also slightly electron-withdrawing.
Effect of the solvent
In water the cation is further stabilised by hydrogen bonding to water molecules (solvation). This is why, in water, methylamine is a stronger base than trimethylamine, even though trimethylamine has more electron-donating groups; in the gas phase, where there is no solvation, trimethylamine is the stronger base.
Conclusion
Electron donation by the alkyl group makes ethylamine the strongest base; delocalisation of the lone pair into the ring makes phenylamine the weakest. Order: ethylamine > ammonia > phenylamine.
The peptide bond
Amino acids join together by a condensation reaction. The \ce{-COOH} group of one amino acid reacts with the \ce{-NH2} group of another: \ce{-OH} from the acid and \ce{-H} from the amine are removed as a molecule of water. The two units are joined by an amide linkage, \ce{-CO-NH-}, called a peptide bond.
Formation of a dipeptide
Two amino acids joined by one peptide bond form a dipeptide. Glycine and alanine can combine in two ways, depending on which \ce{-COOH} group reacts, giving two different dipeptides:
glycylalanine, Gly-Ala
alanylglycine, Ala-Gly
Including Gly-Gly and Ala-Ala, two different amino acids can give four dipeptides.
Formation of a tripeptide
A dipeptide still has a free \ce{-NH2} group at one end and a free \ce{-COOH} group at the other, so it can condense with a third amino acid. The product, with two peptide bonds and two molecules of water lost, is a tripeptide.
Gly-Ala-Gly
Repeating this gives polypeptides; a chain of more than about 50 amino acids is a protein. A chain of n amino acids has n-1 peptide bonds.
Hydrolysis
Peptide bonds are broken by hydrolysis, the reverse reaction. Boiling with 6\,\mathrm{mol\,dm^{-3}} HCl, or the action of enzymes in digestion, gives back the individual amino acids.
Role of peptide bonds in biological systems
- They link amino acids in a definite sequence (the primary structure). This sequence, coded by DNA, decides the shape and job of every protein.
- The \ce{C=O} and \ce{N-H} groups of peptide bonds form hydrogen bonds with each other, folding the chain into the \alpha-helix and \beta-pleated sheet (secondary structure).
- Peptide bonds are strong and stable in the body, so proteins such as keratin and collagen can build hair, skin, tendons and bone.
- Enzymes, hormones (such as insulin), antibodies and haemoglobin are all built from peptide-linked chains.
- In digestion, enzymes (proteases) hydrolyse peptide bonds so that dietary protein is absorbed as amino acids and rebuilt into the body's own proteins.
Reagents and conditions
Phenylamine reacts with nitrous acid, \ce{HNO2}, in the presence of dilute hydrochloric acid at a low temperature (in practice 0 to 5^\circ\mathrm{C}). This reaction is called diazotisation and the product is benzenediazonium chloride. Nitrous acid is unstable and cannot be stored, so it is produced in the mixture from sodium nitrite and hydrochloric acid.
Procedure
- Dissolve phenylamine in excess dilute HCl and cool the solution in an ice bath below 5^\circ\mathrm{C}.
- Cool a solution of sodium nitrite in ice.
- Add the nitrite solution slowly, with stirring, with a thermometer in the mixture so that the temperature never rises above 5^\circ\mathrm{C}.
- Use the diazonium salt solution immediately.
Why the temperature is kept low
- Diazonium salts are unstable. Above about 10^\circ\mathrm{C} they react with water, giving off nitrogen and forming phenol, so the product would be lost: \ce{C6H5N2+ + H2O -> C6H5OH + N2 + H+}.
- Nitrous acid itself decomposes when warm.
- Solid, dry diazonium salts can explode, so they are never isolated.
Significance in organic chemistry
The \ce{-N2+} group is an excellent leaving group because it leaves as \ce{N2}, a very stable gas. So the diazonium salt is a starting point for many aromatic compounds that are hard to make directly.
| Reaction of benzenediazonium chloride | Product |
|---|---|
| warm with water | phenol |
| \ce{CuCl}/HCl or \ce{CuBr}/HBr | chlorobenzene or bromobenzene |
| \ce{CuCN}/KCN | benzonitrile (then benzoic acid) |
| \ce{KI} solution | iodobenzene |
| cold phenol in \ce{NaOH} | 4-hydroxyazobenzene (azo dye) |
| cold phenylamine | aniline yellow (azo dye) |
The azo compounds made by coupling contain the \ce{-N=N-} group joining two aromatic rings. The long delocalised system absorbs visible light, so they are brightly coloured and are used as azo dyes for cloth, food and as indicators such as methyl orange.
Note. The book prints 'below 1^\circ\mathrm{C}'. Its own text and SLO give 'below 5^\circ\mathrm{C}' and 'below 10^\circ\mathrm{C}'; the usual working range is 0 to 5^\circ\mathrm{C}, and the salt decomposes rapidly above 10^\circ\mathrm{C}.
Principle
Electrophoresis separates charged particles in an electric field. A strip of paper or gel is soaked in a buffer of fixed pH and placed between a positive electrode (anode) and a negative electrode (cathode). The mixture is spotted at the centre and a voltage is applied. Positive ions move to the cathode, negative ions to the anode, and neutral species stay where they are. The strip is then sprayed with ninhydrin, which shows the amino acids as coloured spots.
How pH decides the charge
The charge on an amino acid depends on the pH of the buffer compared with its isoelectric point (pI), the pH at which it exists as a zwitterion with no net charge:
- pH below pI: the \ce{-COO-} group is protonated, the ion is positive and moves to the cathode.
- pH equal to pI: zwitterion, no movement.
- pH above pI: the \ce{-NH3+} group loses \ce{H+}, the ion is negative and moves to the anode.
Predicted results for a mixture
| Species (pI) | pH 3 | pH 6 | pH 11 |
|---|---|---|---|
| glycine (6.0) | +, to cathode | 0, stays at start | −, to anode |
| lysine (9.7) | about +2, fastest to cathode | +, to cathode | slightly −, slowly to anode |
| aspartic acid (2.8) | near 0, stays near start | −, to anode | about −2, fastest to anode |
| dipeptide Gly-Ala (about 5.6) | +, to cathode, slower than glycine | nearly 0, hardly moves | −, to anode, slower than glycine |
Dipeptides
A dipeptide has one free \ce{-NH3+} (or \ce{-NH2}) end and one free \ce{-COOH} (or \ce{-COO-}) end, so it gains or loses charge with pH in the same way as an amino acid. Its pI depends on its amino acids, and because it is larger and heavier, it moves more slowly than an amino acid carrying the same charge.
Changes observed as pH changes, and why
- As the pH is lowered, more \ce{-COO-} groups gain \ce{H+}, so every species becomes more positive and the spots move towards the cathode.
- As the pH is raised, more \ce{-NH3+} groups lose \ce{H+}, so every species becomes more negative and the spots move towards the anode.
- At a pH equal to the pI of one component, that component stays on the start line while the others move away, which is a good way to separate it.
- Amino acids with an extra acidic side chain (aspartic acid) are negative at most pH values; those with an extra basic side chain (lysine) are positive at most pH values.
Structure of amino acids
Amino acids contain an amino group, \ce{-NH2} (basic), and a carboxylic acid group, \ce{-COOH} (acidic), on the same carbon atom: \ce{H2N-CHR-COOH}.
Formation of zwitterions
Because one molecule contains both an acid and a base, an internal acid-base reaction takes place. The \ce{-COOH} group donates \ce{H+} to the \ce{-NH2} group of the same molecule. The ion formed has a positive \ce{-NH3+} group and a negative \ce{-COO-} group but no overall charge. It is called a zwitterion (double ion).
glycine
Evidence that amino acids are zwitterions
- They are crystalline solids with high melting points (glycine decomposes at about 233^\circ\mathrm{C}), because strong ionic attractions hold the zwitterions together, as in a salt.
- They are soluble in water (a polar solvent) but insoluble in non-polar solvents such as hexane.
- They move in an electric field unless the pH equals their isoelectric point.
Acid-base (amphoteric) properties
The \ce{-COO-} group is a basic site and the \ce{-NH3+} group is an acidic site, so amino acids react with both acids and bases.
with acid: positive ion
with alkali: negative ion
| pH | Main form of glycine | Net charge |
|---|---|---|
| low (below 6) | \ce{H3N+CH2COOH} | +1 |
| about 6 (pI) | \ce{H3N+CH2COO-} | 0 |
| high (above 6) | \ce{H2NCH2COO-} | −1 |
Significance in different pH environments
- Buffering: amino acids and proteins remove added \ce{H+} or \ce{OH-}, so they help keep the pH of blood and cells nearly constant.
- Solubility: at its pI a protein has no net charge, the molecules do not repel each other, and solubility is lowest; this is used to precipitate proteins (for example casein from milk).
- Separation: the charge changes with pH, so amino acids and peptides can be separated by electrophoresis.
- Protein function: the charges on side chains depend on pH. A large change in pH changes these charges, breaks ionic attractions inside the protein, and can denature an enzyme so that it stops working.
The peptide bond
Amino acids join together by a condensation reaction. The \ce{-COOH} group of one amino acid reacts with the \ce{-NH2} group of another: \ce{-OH} from the acid and \ce{-H} from the amine are removed as a molecule of water. The two units are joined by an amide linkage, \ce{-CO-NH-}, called a peptide bond.
Formation of a dipeptide
Two amino acids joined by one peptide bond form a dipeptide. Glycine and alanine can combine in two ways, depending on which \ce{-COOH} group reacts, giving two different dipeptides:
glycylalanine, Gly-Ala
alanylglycine, Ala-Gly
Including Gly-Gly and Ala-Ala, two different amino acids can give four dipeptides.
Formation of a tripeptide
A dipeptide still has a free \ce{-NH2} group at one end and a free \ce{-COOH} group at the other, so it can condense with a third amino acid. The product, with two peptide bonds and two molecules of water lost, is a tripeptide.
Gly-Ala-Gly
Repeating this gives polypeptides; a chain of more than about 50 amino acids is a protein. A chain of n amino acids has n-1 peptide bonds.
Hydrolysis
Peptide bonds are broken by hydrolysis, the reverse reaction. Boiling with 6\,\mathrm{mol\,dm^{-3}} HCl, or the action of enzymes in digestion, gives back the individual amino acids.
Note. This repeats the first part of long question iii.
Principle
Electrophoresis separates charged particles in an electric field. A strip of paper or gel is soaked in a buffer of fixed pH and placed between a positive electrode (anode) and a negative electrode (cathode). The mixture is spotted at the centre and a voltage is applied. Positive ions move to the cathode, negative ions to the anode, and neutral species stay where they are. The strip is then sprayed with ninhydrin, which shows the amino acids as coloured spots.
How pH decides the charge
The charge on an amino acid depends on the pH of the buffer compared with its isoelectric point (pI), the pH at which it exists as a zwitterion with no net charge:
- pH below pI: the \ce{-COO-} group is protonated, the ion is positive and moves to the cathode.
- pH equal to pI: zwitterion, no movement.
- pH above pI: the \ce{-NH3+} group loses \ce{H+}, the ion is negative and moves to the anode.
Predicted results for a mixture
| Species (pI) | pH 3 | pH 6 | pH 11 |
|---|---|---|---|
| glycine (6.0) | +, to cathode | 0, stays at start | −, to anode |
| lysine (9.7) | about +2, fastest to cathode | +, to cathode | slightly −, slowly to anode |
| aspartic acid (2.8) | near 0, stays near start | −, to anode | about −2, fastest to anode |
| dipeptide Gly-Ala (about 5.6) | +, to cathode, slower than glycine | nearly 0, hardly moves | −, to anode, slower than glycine |
Dipeptides
A dipeptide has one free \ce{-NH3+} (or \ce{-NH2}) end and one free \ce{-COOH} (or \ce{-COO-}) end, so it gains or loses charge with pH in the same way as an amino acid. Its pI depends on its amino acids, and because it is larger and heavier, it moves more slowly than an amino acid carrying the same charge.
Effect of charge and size on migration
- Charge: the force on an ion in the field is proportional to its charge. An ion with charge 2+ is pulled twice as hard as one with 1+, so it moves farther in the same time. The sign of the charge decides the direction.
- Size and mass: larger, heavier molecules meet more resistance (friction) from the paper or gel and the buffer, so they move more slowly. A dipeptide moves more slowly than an amino acid of the same charge.
- So the distance moved depends on the charge-to-size ratio: a small, highly charged ion moves fastest; a large ion with little charge moves least; a neutral species does not move at all.
- By choosing the buffer pH, the charges can be made as different as possible, which gives the best separation of the mixture.
Note. This repeats long question v and adds the effect of size.
FBISE 2026 questions
Questions from the FBISE HSSC-II 2026 (1st Annual) papers that belong to this unit, answered the way an examiner expects.
- ABecomes more stable
- BDecomposes rapidlyAnswer
- CConverts into alkane
- DForms benzene directly
Diazonium salts are unstable. Above about 10^\circ\mathrm{C} the benzenediazonium ion reacts with water, losing \ce{N2} gas and forming phenol: \ce{C6H5N2+ + H2O -> C6H5OH + N2 + H+}. That is why diazotisation is carried out at 0 to 5^\circ\mathrm{C}.
Equations (2 marks)
Nitrous acid is prepared in the mixture from sodium nitrite and dilute hydrochloric acid, and reacts with phenylamine in the cold (diazotisation):
Reason for the low temperature (1 mark)
Benzenediazonium chloride is unstable. If the mixture warms up (above about 10^\circ\mathrm{C}) it decomposes, giving off nitrogen gas and forming phenol, so the product is lost. Nitrous acid also decomposes on warming. The mixture is therefore kept ice-cold and the salt is used at once.
Note. The paper (like the book's long question iv) says 'below 1^\circ\mathrm{C}'. The book's text uses 'below 5^\circ\mathrm{C}'; the usual range is 0 to 5^\circ\mathrm{C}. Either value earns the mark if the reason is given.
Zwitterionic form (1 mark)
In an amino acid, \ce{H2N-CHR-COOH}, the \ce{-COOH} group gives a proton to the \ce{-NH2} group of the same molecule. The result is the zwitterion \ce{H3N+-CHR-COO-}: it has a positive and a negative part but no overall charge. For glycine (R = H):
Acidic site (1 mark)
The \ce{-NH3+} group is the acidic site: it can donate \ce{H+} to a base, \ce{H3N+CH2COO- + OH- -> H2NCH2COO- + H2O}.
Basic site (1 mark)
The \ce{-COO-} group is the basic site: it can accept \ce{H+} from an acid, \ce{H3N+CH2COO- + H+ -> H3N+CH2COOH}.
Two factors that affect the basic strength of amines
- Availability of the lone pair on nitrogen. A base accepts \ce{H+} with the nitrogen lone pair. Electron-donating alkyl groups (+I effect) increase the electron density on nitrogen and make the base stronger; delocalisation of the lone pair into a benzene ring (resonance) makes it less available and the base weaker.
- Stability of the cation formed. The more the positive charge of \ce{RNH3+} is spread out (by alkyl groups) and stabilised by hydrogen bonding with water (solvation), the more readily the amine accepts \ce{H+}.
Correct order and explanation
All three accept a proton: \ce{RNH2 + H2O <=> RNH3+ + OH-}. A lower \mathrm{p}K_b means a stronger base.
Ethylamine > ammonia. The ethyl group is electron-donating. It pushes electron density onto nitrogen, so the lone pair attracts \ce{H+} more strongly (factor 1). It also spreads the positive charge in \ce{CH3CH2NH3+}, making this ion more stable than \ce{NH4+} (factor 2).
Ammonia > phenylamine. In phenylamine the nitrogen lone pair overlaps with the \pi electrons of the benzene ring and is delocalised over the ring, so it is far less available for \ce{H+} (factor 1). On protonation this delocalisation is lost, so the phenylammonium ion gains no extra stability (factor 2).
The resonance structures show negative charge at positions 2, 4 and 6 of the ring and a positive charge on nitrogen: the lone pair is shared with the ring. This is also why phenylamine reacts so easily with bromine water.
So electron donation makes ethylamine the strongest base and delocalisation makes phenylamine the weakest.
Note. The paper prints the order as 'Phenylamine > Ammonia > Ethylamine'. This is reversed: it is the order of increasing basic strength written with '>' signs. The correct order of basic strength is ethylamine > ammonia > phenylamine (\mathrm{p}K_b 3.27, 4.75, 9.36). In the exam, write the correct order, state that the printed order is reversed, and explain it.
- ANitrogenAnswer
- BCarbon dioxide
- COxygen
- DHydrogen
On warming with water the \ce{-N2+} group leaves as nitrogen gas and phenol is formed: \ce{C6H5N2+Cl- + H2O -> C6H5OH + N2 ^ + HCl}.
- A\ce{(CH3)3N}
- B\ce{C6H5NH2}
- C\ce{CH3NH2}Answer
- D\ce{NH3}
Methylamine (\mathrm{p}K_b 3.36) is the strongest base here. Trimethylamine has more electron-donating groups, but in water its cation \ce{(CH3)3NH+} has only one \ce{N-H} bond to hydrogen-bond with water and is crowded by three methyl groups, so it is poorly solvated (\mathrm{p}K_b 4.20). Ammonia (4.75) and phenylamine (9.36) are weaker still.
Trimethylamine would be the answer only in the gas phase, where solvation plays no part.
Note. The book compares only ammonia, ethylamine and phenylamine. Using the inductive effect alone would suggest (CH3)3N, which is the trap in this question.
In an amide, \ce{RCONH2}, the nitrogen is attached to a carbonyl group. The lone pair on nitrogen is delocalised onto the \ce{C=O} group and the electronegative oxygen atom (resonance), so it is not free to bond to a proton.
The carbonyl group is also strongly electron-withdrawing, which lowers the electron density on nitrogen further. In amines the lone pair is localised on nitrogen and alkyl groups push electrons towards it (+I), so amines accept protons readily. As a result amide solutions are neutral while amine solutions are alkaline.
Two factors that affect the basic strength of amines
- Availability of the lone pair on nitrogen. A base accepts \ce{H+} with the nitrogen lone pair. Electron-donating alkyl groups (+I effect) increase the electron density on nitrogen and make the base stronger; delocalisation of the lone pair into a benzene ring (resonance) makes it less available and the base weaker.
- Stability of the cation formed. The more the positive charge of \ce{RNH3+} is spread out (by alkyl groups) and stabilised by hydrogen bonding with water (solvation), the more readily the amine accepts \ce{H+}.
Correct order and explanation
All three accept a proton: \ce{RNH2 + H2O <=> RNH3+ + OH-}. A lower \mathrm{p}K_b means a stronger base.
Ethylamine > ammonia. The ethyl group is electron-donating. It pushes electron density onto nitrogen, so the lone pair attracts \ce{H+} more strongly (factor 1). It also spreads the positive charge in \ce{CH3CH2NH3+}, making this ion more stable than \ce{NH4+} (factor 2).
Ammonia > phenylamine. In phenylamine the nitrogen lone pair overlaps with the \pi electrons of the benzene ring and is delocalised over the ring, so it is far less available for \ce{H+} (factor 1). On protonation this delocalisation is lost, so the phenylammonium ion gains no extra stability (factor 2).
So electron donation makes ethylamine the strongest base and delocalisation makes phenylamine the weakest.
Note. The paper prints the order as 'Phenylamine > Ammonia > Ethylamine'. This is reversed: it is the order of increasing basic strength written with '>' signs. The correct order of basic strength is ethylamine > ammonia > phenylamine (\mathrm{p}K_b 3.27, 4.75, 9.36). In the exam, write the correct order, state that the printed order is reversed, and explain it.
Stronger base (1 mark)
Methylamine, \ce{CH3NH2}, is the stronger base (\mathrm{p}K_b 3.36, against 4.75 for ammonia).
Reason (2 marks)
Both bases accept a proton with the lone pair on nitrogen: \ce{CH3NH2 + H2O <=> CH3NH3+ + OH-}. The methyl group is electron-donating (positive inductive effect). It increases the electron density on the nitrogen atom, so the lone pair is more available and attracts \ce{H+} more strongly than in ammonia. The methyl group also spreads the positive charge of the \ce{CH3NH3+} ion, so this ion is more stable than \ce{NH4+}, which also favours protonation.
Note. The paper prints 'strenght'; corrected to 'strength'.
Exam focus
- State two factors that affect the basic strength of amines and explain the order ethylamine > ammonia > phenylamine. (long)Asked in both new 2026 sets (Set B Q.4 OR, 7 marks; Set D Q.5 OR, 6 marks), both with the order printed in reverse.Go to answer
- Why are amides much weaker bases than amines? (short)2026 Set D Q.2 (x) OR and a book short question; the resonance structure earns the marks.Go to answer
- Write the equations for diazotisation of phenylamine and explain why it is done below 5^\circ\mathrm{C}. (short)2026 Set B Q.2 (viii) OR and MCQ 9; the book asks it as short iii and long iv.Go to answer
- Draw the zwitterion of an amino acid and label its acidic and basic sites; explain amphoteric behaviour. (short)2026 Set B Q.2 (ix); also a book short and long question.Go to answer
- Predict the results of electrophoresis of amino acids and dipeptides at pH 3, at the pI and at pH 11. (long)Three book questions; use the pH versus pI rule, then charge and size.Go to answer
- Show the formation of a dipeptide and a tripeptide and the role of peptide bonds. (long)Two book long questions; name the condensation and show the water lost.Go to answer
- Hydrolysis of nitriles with dilute acid, and with dilute alkali followed by acidification. (long)SLO reaction and a book long question; conditions and both sets of equations are needed.Go to answer
- Coupling of benzenediazonium chloride with phenol in NaOH; the azo group and azo dyes. (short)SLO reaction; the structure of the azo group was a book exercise MCQ.Go to answer
- Why is methylamine more basic than ammonia, and why is trimethylamine weaker than methylamine in water? (short)Old-syllabus 2026 Q.2 (vi) OR and Set D MCQ 12 test the inductive effect and solvation.Go to answer
- Preparation of primary and secondary amines, and reduction of nitriles and amides with \ce{LiAlH4}. (short)Four book exercise MCQs and a short question test these reagents and conditions.Go to answer
- Reaction of phenylamine with bromine water. (short)Two book exercise MCQs; the balanced equation needs 3 Br2.Go to answer